Write a C++ program to perform exception handling for Divide by zero Exception.




Program Algorithm:
Step 1: Include the header files
Step 2: Declare the variables a,b,c.
Step 3: Read the values a,b,c,.
Step 4: Inside the try block check the condition.
a. if(a-b!=0) then calculate the value of d and display.
b. otherwise throw the exception.
Step 5: Catch the exception and display the appropriate message.

Program Code in C++:
#include<iostream.h>
#include<conio.h>
void main()
{
int a,b,c;
float d;
clrscr();
cout<<"Enter the value of a:";
cin>>a;
cout<<"Enter the value of b:";
cin>>b;
cout<<"Enter the value of c:";
cin>>c;
try
{
if((a-b)!=0)
{
d=c/(a-b);
cout<<"Result is:"<<d;
}
else
{
throw(a-b);
}
}
catch(int i)
{
cout<<"Answer is infinite because a-b is:"<<i;
}
getch();
}





Program Output:
Enter the value for a: 20
Enter the value for b: 20
Enter the value for c: 40
Answer is infinite because a-b is: 0
Mukesh Rajput

Mukesh Rajput

I am a Computer Engineer, a small amount of the programming tips as it’s my hobby, I love to travel and meet people so little about travel, a fashion lover and love to eat food, I am investing a good time to keep the body fit so little about fitness also..

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