Command Line Argument

Write a C program to read arguments at the command line and display it.

Algorithm:

1. Start

2. Pass a to arguments argc and argv in the main function

3. Check the condition argc equal to 2 then printf the argv[1] value

4. else if argc is greater than 2 the print Too many arguments supplied

5. else One argument expected

6. Stop

Program Code:

#include<stdio.h> 

#include<string.h> 

void main(int argc,char *argv[]) 

{ 

int i; printf("\n total no of arguments=%d",argc); 

for(i=0;i<argc;i++) 

printf("\n args[%d]=%s",i,argv[i]); 

}

Thanks

Mukesh Rajput