Class Programming

Write a C++ program with different class related through multiple inheritance and demonstrate the use of different access specifiers by means of member variables and member functions.

Implementation of the above problem:

#include<iostream.h>

#include<conio.h>

class base1

{

protected:

int z;

private:

int y;

public:

int x;

void set_value(int xx,int yy, int zz)

{

x=xx;

y=yy;

z=zz;

}

void display1()

{

cout<<"\nX="<<x;

cout<<"\ny="<<y;

cout<<"\nZ="<<z;

}

};

class base2

{

protected:

int a;

private:

int b;

public:

int c;

void set_values(int aa,int bb, int cc)

{

a=aa;

b=bb;

c=cc;

}

void display2()

{

cout<<"\nA="<<a;

cout<<"\nB="<<b;

cout<<"\nC="<<c;

}

};

class derived:public base1,private base2

{

public:

void display()

{

a=100;

c=200;

cout<<"\nValue of X in derived class="<<x;

//cout<<"\nValue of Y in derived class="<<y; base1::y not accessible

cout<<"\nValue of Z in derived class="<<z;

cout<<"\nValue of A in derived class="<<a;

//cout<<"\nValue of B in derived class="<<b;base2::b not accessible

cout<<"\nValue of C in derived class="<<c;

}

};

void main()

{

clrscr();

derived d;

d.set_value(10,20,30);

//d.set_values(100,200,300);not accessible when derived as private

d.display1();

//d.display2(); not accessible when derived as private

d.display();

cout<<"\nValue of X in main="<<d.x;

//cout<<"\nValue of Y in main="<<d.y; base1::y not accessible

//cout<<"\nValue of Z in main="<<d.z; base1::z not accessible

//cout<<"\nValue of C in main="<<d.a; base2::a not accessible

//cout<<"\nValue of B in main="<<d.b; base2::b not accessible

//cout<<"\nValue of C in main="<<d.c; base2::c not accessible

getch();

}

Thanks

Mukesh Rajput