Write a main ( ) function that gets values from the user to test this function.

Raising a number n to a power p is the same as multiplying n by itself p times. Write a function called power ( ) that takes a double value for n and an int value for p, and returns the result as the double value. Use a default argument of 2 for p, so that if this argument is omitted, the number will be squared. Write a main ( ) function that gets values from the user to test this function.

Implementation of the above problem:

#include<iostream.h>

#include<conio.h>

double power(double n,int p=2);

int main()

{

double n,r;

int p;

char c;

clrscr();

cout<<"enter the number:";

cin>>n;

do

{

cout<<"do you want to enter power(y/n)?:";

cin>>c;

if(c=='y')

{

cout<<"enter the power to be raised:";

cin>>p;

r=power(n,p);

}

else

{

if(c=='n')

{

p=2;

r=power(n);

}

else

cout<<"invalid choice\n";

}

}

while(c!='y'&&c!='n');

cout<<n<<"^"<<p<<"("<<n<<" raised to the power "<<p<<")="<<r;

getch();

return 0;

}

double power(double n,int p)

{

double r=1;

int i;

if(p<0)

r=1/power(n,-p);

else

for(i=1;i<=p;i++)

r=r*n;

return(r);

}

Thanks

Mukesh Rajput