Create the equivalent of a four function calculator. The program should request the user to enter a number, an operator, and another number.

Create the equivalent of a four-function calculator. The program should request the user to enter a number, an operator, and another number. It should then carry out the specified arithmetical operation: adding, subtracting, multiplying, or dividing the two numbers. (It should use a switch statement to select the operation). Finally, it should display the result. When it finishes the calculation, the program should ask if the user wants to do another calculation. The response can be Y or N. Some sample interaction with the program might look like this.

Enter first number, operator, second number: 10/ 3

Answer = 3.333333

Do another (Y/ N)? Y

Enter first number, operator, second number 12 + 100

Answer = 112

Do another (Y/ N) ? N

Implementation of the above problem:

#include<iostream.h>

#include<conio.h>

int main()

{

char c,operatr;

double operand1,operand2;

clrscr();

do

{

cout<<"Enter first number,operator,second number:";

cin>>operand1>>operatr>>operand2;

switch(operatr)

{

case '+':cout<<"Answer="<<operand1+operand2;

break;

case '-':cout<<"Answer="<<operand1-operand2;

break;

case '*':cout<<"Answer="<<operand1*operand2;

break;

case '/':cout<<"Answer="<<operand1/operand2;

break;

default:cout<<"invalid operator";

}

do

{

cout<<"\nDo another(y/n)?:";

cin>>c;

if(c!='y'&&c!='n')

cout<<"invalid choice";

}while(c!='y'&&c!='n');

}while(c=='y');

return 0;

}

Thanks

Mukesh Rajput