Class Programming

Create a class rational which represents a numerical value by two double values- NUMERATOR & DENOMINATOR. Include the following public member Functions: 

constructor with no arguments (default).

constructor with two arguments.

void reduce( ) that reduces the rational number by eliminating the highest common factor between the numerator and denominator.

Overload + operator to add two rational number.

Overload >> operator to enable input through cin.

Overload << operator to enable output through cout.

Write a main ( ) to test all the functions in the class.

Implementation of the above problem:

#include<iostream.h>

#include<conio.h>

#include<process.h>

class rational

{

private:

int num;

int den;

int lcm(int a,int b);

int hcf(int a,int b);

public:

rational()

{

num=0;

den=1;

}

rational(int n,int d=1)

{

if(d==0)

{

cout<<"denominator can't be zero";

getch();

exit(1);

}

else

{

num=n;

den=d;

}

}

rational reduce()

{

rational temp;

int h=hcf(num,den);

temp.num=num/h;

temp.den=den/h;

return temp;

}

rational operator +(rational r)

{

int l,t1,t2,x1,x2,den1,den2,p;

rational ans;

if(den<0)

den1=-den;

else

den1=den;

if(r.den<0)

den2=-r.den;

else

den2=r.den;

p=lcm(den1,den2);

if((den<0&&r.den>0)||(den>0&&r.den<0))

l=-p;

else

l=p;

ans.den=l;

t1=l/den;

t2=l/r.den;

x1=num*t1;

x2=r.num*t2;

ans.num=x1+x2;

return ans;

}

friend istream& operator >> (istream& s,rational& r);

friend ostream& operator << (ostream& s,rational& r);

};

int rational::lcm(int a,int b)

{

int i,lcm=1;

while(!(a==1&&b==1))

{

i=2;

while(!(a%i==0||b%i==0)&&i<(a>b?a:b))

i++;

lcm*=i;

if(a%i==0)

a/=i;

if(b%i==0)

b/=i;

}

return lcm;

}

int rational::hcf(int a,int b)

{

int r=a%b;

while(r)

{

a=b;

b=r;

r=a%b;

}

return b;

}

istream& operator >>(istream& s,rational& r)

{

int a,b;

char c;

s>>a>>c>>b;

if(c!='/')

{

cout<<"use of invalid notation";

getch();

exit(0);

}

if(b==0)

{

cout<<"denominator can't be zero.";

getch();

exit(1);

}

r.num=a;

r.den=b;

return s;

}

ostream& operator <<(ostream& s,rational& r)

{

if(r.den==1)

s<<r.num;

else

{

if(r.den==-1)

s<<-r.num;

else

s<<r.num<<'/'<<r.den;

}

return s;

}

int main()

{

clrscr();

rational r1,r2,r3;

cout<<"enter r1:";

cin>>r1;

cout<<"enter r2:";

cin>>r2;

r3=r1+r2;

cout<<r1<<" + "<<r2<<" = "<<r3<<" = "<<r3.reduce();

getch();

return 0;

}

Thanks

Mukesh Rajput